how to solve new york times sudoku

Every such easy fill at this stage is a bonus. Results of the actions taken shown below. Copyright: Atanu Chaudhuri and respective Authors. Enjoy also learning how to solve Sudoku hard in easy steps. If we get one, we should get usually a breakthrough in one step or two. Enjoy also learning how to solve Sudoku hard in easy steps. Turning attention first on promising zone C6 we get the breakthrough DS [6,8] in R5C6 by DSA reduction of [1,2,9] from column C6 DS [1,2,6,8,9]. R5C5 7 by DSA reduction of [1,5,8] from DS [1,5,7,8] in C5 -- R6C4 4 by DS reduction of [3,8,9] in C4 from DS [3,4,8,9] in R6. Be VERY careful about your notes. R5C3 9 by reduction of 3 -- R4C3 2 by exception in C3. With this, two more empty cells R8C7 and R8C9 are left for 8 in R8. We are only concerned with the most important fact that digit 5 can appear in only these two cells and NOWHERE ELSE IN THE TWO PARENT ZONES. Alternately this lock on 6 acts as if 6 actually exists in R8 and that's why a lock on a digit can be used for a scan for the digit. R6C5 3 by scan for 3 in R4, R5, C4 -- R8C6 3 by scan in R7, C4, C5. R1C7 2 by scan for 2 in R2, R3, C8 -- R1C8 6 by scan for 6 in R2, R3. By the double digit scan, first the Cycle is formed and then the valid cell R6c1 4 by reduction of [1,8] because of the property of the Cycle. This is the quick method of parallel scan for digit 8 on empty cells of the row R8. R9C8 2 by scan for 2 in C7 -- R9C3 5 by reduction -- R8C3 2 by reduction -- R9C4 4 by reduction -- R8C4 5 by reduction and exception. Enjoy solving Sudoku hard. Description- Self Solving Sudoku- Slice and Dice- Triple Subset- Hidden Block Pair- Locked Candidates Pointing- New York Times Sudoku Hard October 14, 2022 -. If yes, then we have provided all the NY Times Sudoku Answers. Because of 8 in central middle major square, R5C6 6 by reduction of 8 -- R8C6 8 by reduction of 6 -- R8C5 6 by reduction of 8. In the final solution, 6 can appear in only one of these two cells and in no other cell of the parent bottom right major square or the parent row R8. Both digits 1 and 8 appear together in column C1 but not in any cell of the left major square. For example, in this case, reduction of 7 from DS of R6C2 gives us a valid cell hit as R6C2 2. With 5 in R1C1, R7C1 1 by reduction -- R8C1 2 by reduction -- R8C3 6 by reduction -- R8C2 5 by reduction -- R8C5 1 by reduction -- R3C5 5 by reduction -- R9C4 8 by reduction -- R9C2 3 by reduction -- R9C3 9 by reduction -- R7C3 8 by reduction -- R4C3 7 by reduction -- R4C2 8 by reduction. Cycle reduces possible digit subset for R7C4, R7C6 to [5,7] and with [7] in C6 we get the breakthrough R7C5 5 by reduction of 7 followed by R7C4 7 by exception. Now in addition, a third possible digit subset of [2,6] is formed in R8C3 by DSA reduction of [1,5] from possible digit subset [1,2,5,6] in R8. With 1 in R7C1, R7C7 5 by reduction -- R9C7 1 by reduction -- R9C4 5 by exception in R9 -- R7C4 9 by exception in whole game. Next identify the advanced technique of Parallel scan for 8 on empty cells of R8: 8 in bottom left major square eliminates R8C1, R8C2, R8C3 for 8 and 8 in C9 eliminates R8C9 for 8 leaving the single cell R8C7 for 8 -- R8C7 8. In this case observe that by scan for 6 in R8, digit placement of digit 6 is restricted to only two cells in R8, R8C7 and R8C9. This is a hard Sudoku puzzle that needed multiple breakthroughs by advanced Sudoku techniques. Though number of digit 3 is small, we identify first a single digit lock for 3 in R9C7, R9C9 by cross scan for 3 in R7, C8. Effect of this critically important single digit lock is reduction of 6 in possible digit subset [1,5,6] to [1,5] in R8C5. With 7 in R4C3, R1C3 3 by reduction -- R1C2 7 by reduction. This helps to form a new Cycle (1,5,8) in R3C5, R8C5, R9C5 -- R1C5 6 by reduction. This is shown by "5" in the two cells. Elimination of the cells in R6 for 7 by parallel scan are shown by colored arrows in the game status figure shown below. Play the USA TODAY Sudoku Game. Starting the solution process, first valid cell success by row column is for 2: R8C7 2 by scan for 2 in R9, C8, C9 -- R7C1 2 by scan for 2 in R8, R9. Instead of scanning the promising empty cells of a major square FOR A SINGLE DIGIT, in a double digit scan, the promising empty cells of a major square are scanned for TWO DIGITS TOGETHER. Nevertheless, a distinction between hard, medium and easy Sudoku categories can be made. This creates an opportunity for us to apply advanced technique of double digit scan to get a valid cell hit. R2C3 5 by parallel digit scan for 5 on empty cells of C3: 5 in R1 debars R1C3 for 5, 5 in left middle major square debars R4C3, R5C3 for 5 leaving single cell R2C3 for 5 -- R2C5 1 by reduction of [5,8] from DS [1,5,8] in C5 -- R4C5 5 by reduction of 1 -- R4C4 1 by reduction and R1C5 8 by exception in C5. For easier lower level Sudoku games this systematic method of row column scan should provide a smooth path to the final solution. 3 Sudoku types . By this parallel scan for 5 on empty cells of row R2, only one cell R2C5 is left placing digit 5. Every such easy fill at this stage is a bonus. DS in C1 [1,2,5,7] reduced by [2,7] in R7 to form DS [1,5] in R7C1, reduced by 7 in R8 to form DS [125] in R8C1 and reduced by 2 in R9 to form DS [1,5,7] in R9C1. An often asked questions is, "What makes a Sudoku puzzle hard?". Fill as many cells as you can by row-column scan. The possible digit subset in the three empty cells is [1,4,8]. Before going through the solution solve the puzzle first. Solving a puzzle with a pen is a very different beast than using software that can fill and track pencil marks, highlight all cells with a given candidate and support non destructive cell highlights for chains. In the process, an awkward shaped Cycle (1,2,5,6) in bottom left major square formed. It is followed immediately by a second valid cell for 7 in the promising neighborhood of left middle major square: R5C2 7 by scan for 7 in R6. Observe that the two digits [1,8] appear together in R6 and also in C9, but do not appear in the right middle major square. Breakthrough R3C3 4 by DSA reduction of [3,7,8,9] from possible digit subset of [3,4,7,8,9] -- R3C7 8 by reduction from DS [4,8] -- R1C7 4 by reduction and exception in top right major square. Since the launch of The Crossword in 1942, The Times has captivated solvers by providing engaging word and logic games. Reduced DS in two empty cells in C8 is [2,9] -- R2C8 2 by reduction of 9 by R2 -- R2C1 8 by reduction -- R2C7 6 by reduction -- R2C4 3 by exception in R2. Target is to get two-digit possibilities first. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). In this game having no success with 1 or 2 by row column scan select digit 3 as promising and get a few easy placements. $(1, 3, 6) \cup (3, 4, 7, 9) \cup (1, 3, 5)=(1, 3, 4, 5, 6, 7, 9)$. With six digits filled in the left middle major square, it is a very promising zone to look for more valid cell hits. Because of the series of early breakthroughs by advanced digit patterns, the Sudoku hard could be solved rather easily. R4C4 4 by scan for 4 in R5, R6, C6 -- R4C6 5 by exception in R4 -- R5C5 7 by scan for 7 in C4, C6. Note: To know more on DSA reduction technique, click on the above internal link and return (after going through it) by clicking on browser back button. So we'll next start evaluating 2 or 3 digit possible digit subsets DSs in . The elimination of four empty cells for 5 in row R2 is shown by red arrows in the Stage 2 solution figure below. With much of the empty cells filled up with valid digits, short length possible digits are evaluated conveniently in promising zones by possible digit analysis technique. Section below explains in a bit of detail the process of enumerating digits possible in a cell. After speed of solution, reducing labor being the main objective, we won't enumerate 4 or 5-digit possibilities or enumerate possible digits for ALL the cells. Description- Self Solving Sudoku- Slice and Dice- Locked Candidates Pointing- Triple Subset- Pair- Locked Candidates Claiming- New York Times Sudoku Hard October 21, 2022- Repeat from 19 January 2019- Watch as a Sudoku Classic puzzle is clearly solved step by step.- Stop video, solve the next square, play to check- Each square is solved in order of easy to hard.- Thanks for watching- Share if you like- A more important issue is reminding us to:- Observe the 6 foot rule- Wash our hands- Cough into our elbows- Avoid touching our faces- Wear a better mask- Be glad to get the jabs- Lets keep everyone safe- Cheers#RSOUDREUNSUDOKU#ResolviendoSudoku#SudokuNYT#NYTimes#Sudoku#Puzzle#Puzzles#Solutions These are rough figures drawn from experience. About New York Times Games. By the way, Sudoku hard solution techniques are included with many of the solutions. Wordle players can use these five hints to solve puzzle #500. R7C4 1 by DSA reduction of 9 from DS [1,9] in R7 -- R7C5 9 by exception in R7. More Sudoku hard puzzles you may like to solve and learn how to solve. Primarily, with only two cells left for the two digits, a breakthrough Cycle of (1,8) is formed in a single strike and it leaves only the cell R6C1 for digit 4 by exception in left middle major square. These are rough figures drawn from experience. There is no metric or measurement to decide for sure that a Sudoku puzzle is hard, or not so hard. Cycle (2,6) in two empty cells R6C3, R6C4 and DS [2,6] in R8C3 by DSA reduction of [1,5] from possible digits [1,2,5,6] in R7 -- a breakthrough Cycle (2,6) formed in R6C3, R8C3. For full enjoyment, avoid looking into any solution as well as the answer. In addition Cycle (1,9) is formed in R9C4, R9C6. This prompts us to look for a valid cell caused by this single digit lock and thus discover the difficult to identify R2C5 5 by parallel digit scan for 5 on empty cells of R2. Because of the Cycle (6,7) in R7, reduced possible digit subset in three empty cells of R7 is [1,4,9] -- breakthrough R7C3 4 by DSA reduction of [1,9] from DS [1,4,9]. There is no metric or measurement to decide for sure that a Sudoku puzzle is hard, or not so hard. Identify Single digit lock on 6 in R7C7, R7C9 by scan for 6 in R8 -- this lock on 6 participates in next valid cell R9C2 6 by scan for 6 in R7 by the lock, 6 in R8 and 6 in C1. You can include the QR code to any puzzle that is 9x9, for instance, to make it unique. For example, in this case, after you place 8 in R8C7, it will be easy for you to identify a Cycle of (1,4,5,7) in rest four empty cells without specifically evaluating the possible digit subsets in these cells. The New York Times publishes three puzzle challenges every [] Use row-column scan, the simplest method to get a unique digit for a cell. An often asked questions is, "What makes a Sudoku puzzle hard?". With 3 in R8C6, R8C7 7 by reduction -- R9C7 3 by reduction -- R8C5 6 by reduction -- R9C5 7 by reduction. If you cannot logically place a value in a cell then do not place that value in a cell. To skip the section, click here. This single digit lock has been formed by Cross-scan for 6 in R9, C1 and the Cycle (2,6) formed by DSA in R6C3, R8C3. By possible digit analysis we have the DSs in R4C3, R5C3 and R6C3 as [1,6], [1,6,7] and [1,6,7]. An interesting property of a valid cell by parallel digit scan is, there will always be an associated Cycle after you put the valid digit in its identified cell. We eliminate repeated digits when considering digits of two or three zones together. In the process we may get valid cells, but otherwise our lookout is for identifying for a single digit lock by cross scan. Next valid cell R5C6 6 will be shown in next stage. It's a pleasant surprise to identify that a Cycle of [1,2,5,6] is formed in the four cell DSs in R7C1, R8C1, R8C2 and R8C3. R3C8 1 by scan for 1 in R2, C7, C9 R2C1 9 by reduction of [2,6] in R2 from DS [2,6,9] in top left major square -- R2C1 6 by reduction of 2 in C1 -- R3C2 2 by exception in top left major square R4C2 6 by exception in C2. It is a fairly hard Sudoku puzzle. We'll close here and explore the rest later. For example, R5C5 2 by DSA reduction of [1,5] in the parent top middle major square itself from the possible digit DS of [1,2,5] in C5. By the way, Sudoku hard solution techniques are included with many of the solutions. Solution to the New York Times Sudoku Hard, 15th February, 2021: Stage 1: Early breakthroughs by Single digit lock and parallel scan Use row-column scan, the simplest method to get a unique digit for a cell. R3C2 4 by scan for 4 in R2, C1, C3 -- R3C3 1 by scan for 1 in R2, C1 -- R6C3 8 by reduction -- R6C2 1 by reduction -- R2C3 7 by reduction -- R2C8 6 by reduction -- R2C2 8 by reduction and exception -- R1C8 4 by reduction -- R1C7 5 by reduction -- R1C1 6 by reduction and exception in R1 -- R7C1 7 by reduction -- R3C1 5 by reduction. Hint #1: The word contains three vowels (madness isn't it) one of which, in a different word structure, could be a consonant. This breakthrough DS of [6,8] joins with [6,8] in R8C6 to form breakthrough Cycle [6,8] in C6 reducing DS in C6 to [1,2,9] and causing the breakthrough in R6C6 2 by reduction of [1,9] from C6 DS [1,2,9] -- R6C3 4 by reduction of [2,8] -- R6C4 8 by exception in R6 -- R1C2 4 by scan for 4 in R3, C1, C3. In easy ones it can be 36 or more. How debt-for-climate swaps can help solve low-income countries' fiscal and environmental challenges at the same time First valid cell by row column scan is for 5: R4C2 5 by scan for 5 in R5, R6. By the way, Sudoku hard solution techniques are included with many of the solutions. Once a few cells are filled in a zone, enumerating the rest gets easier. An easy catch by opportunistic scan for 9: R9C9 9 by scan in R7, R8. By the way, Sudoku hard solution techniques are included with many of the solutions. Chose between Classic, Monster, Kids and Squiggly, and easy, medium, hard and very hard skill levels We "live-solve" the New York Times "Hard" Sudoku on 31 Jan 19. Next breakthroughs by forming Cycle (8,9) in R7C, R7C9 by DSA reduction in both cases by [5,7] from possible digit subset [5,7,8,9] in four empty cells of R7. Most important breakthrough at this stage finally has been provided by the single digit lock on 6 in R8C2, R8C3. The New York Times Sudoku Hard, 17th February, 2021 Before going through the solution solve the puzzle first. To preserve the breakthrough digit patterns the stage is closed here with status shown below. This creates Cycle (7,8) in R4. . An often asked questions is, "What makes a Sudoku puzzle hard?". With 6 in R9C5, R8C2 9 by reduction -- R9C2 6 by reduction. With 9 in R8C2, R8C9 4 by reduction -- R8C9 4 by reduction -- R9C9 9 by reduction. It reduces the possible digit subset DS in right middle major square to [4,5,7,9] -- breakthrough valid cell R6C8 5 by reduction of [4,7,9] (with [4,7] in C8 and 9 in C6) from DS [4.5.7.9] -- followed by R7C8 3 by DSA reduction of [1,5,7] from DS [1,3,5,7] in C8 -- R7C9 7 by reduction of [1,5] from DS [1,5,7]. Nevertheless, a distinction between hard, medium and easy Sudoku categories can be made. To solve quickly you need to concentrate. This makes the digit invalid in any other cell in the row or column in which the digit is locked. If you are alert for detecting a parallel scan opportunity, breakthrough would be much quicker. The joy of discoveries will then all be yours. R4C7 7 by scan for 7 in C8, C9 -- R3C7 9 by reduction of 8 from DS [8,9] in R3 -- R3C9 8 by exception in R3 -- R7C9 9 by reduction -- R7C8 8 by reduction -- R4C9 4 by reduction of 9 from DS [4,9] in R4 -- R4C8 9 by exception -- R9C9 3 by exception in C9. If you get stuck, we're here to help with handy hints, as we are every day. This breakthrough gives us two more valid cells, R3C7 8 by reduction from DS [4,8] -- R1C7 4 by reduction and exception in top right major square. This will result in a series of valid cells and is a major breakthrough. With 5 in R1C1, R3C2 2 by reduction -- R5C2 6 by reduction -- R6C3 2 by reduction -- R6C4 6 by reduction -- R5C6 1 by reduction -- R5C4 2 by reduction. This is how we get a breakthrough valid cell R8C7 8 by parallel scan. As a subscriber, you have 10 gift articles to give each month. You could have identified the formation of this Cycle first to get the breakthrough. With this basic concept in place start row column scan for the lowest digit 1 and continue the process till a digit is finished or ends in a block of no more success. This Sudoku hard is a challenging puzzle rich with Sudoku digit patterns. Copyright: Atanu Chaudhuri and respective Authors. With 4 in R1C8, R5C8 9 by reduction -- R5C7 4 by reduction -- R3C7 9 by exception in C7 -- R3C8 9 by exception in whole game. Select a Word Game to learn more: Wordle. First success by row-column scan: R8C8 4 because of 4 in R7, R9 -- R9C9 2 by scan for 2 in R7, C7. Leftover three digits in C3 form a Cycle (1,6,7) in R4C3, R5C3, R6C3. This creates an opportunity for us to apply advanced technique of double digit scan to get a breakthrough Cycle (1,8). Popular sites for tracking the pandemic such the New York Times Covid tracker have become less useful because they rely on PCR testing; most infected people, if they do test, are using antigen . Because of this effect of limiting the digits inside the Cycle, the possible digit subset in the column C3 is reduced to [3,4,7,8,9] and this creates the breakthrough in R3C3 4 by DSA reduction of [3,7,8,9] (with [8,9] in parent top left major square and [3,7] in second parent R3) from DS [3,4,7,8,9] in C3. This NY Times Sudoku puzzle with only 23 filled cells is fairly hard and well-balanced. This reduces [1,5] from DS [1,5,7] to produce a major breakthrough of R9C1 7. That's why for speed, we prefer to identify parallel digit scan possibilities. But the cell R8C9 is again disallowed for digit 8 by the presence of 8 in C9 and the only cell left in R8 for digit 8 is the cell R8C7. Consider the row column cross-scan: With digit 5 in R4C2, and R7C9, 5 can appear only in two cells R8C3 and R9C3 of bottom left major square Thus the digit 5 is locked in C3 as well as in the parent major square. Analyze in which cell digit 5 can appear in R2. Possible digit subset in central middle major square reduced to [1,4,5,7] -- R5C2 5 by DSA reduction of [2,6] in R5 from [2,5,6] possible digit subset in C2. The Hint button will highlight the next logical square to solve that is empty or incorrect. Set union is technical, but this we do by common sense and do naturally. Unnecessary enumeration of possible digit subsets in empty cells is avoided to speed up the solution. Now do a parallel scan for 1 in empty cells of column C6 to get the valid cell R1C6 1. Strategy adopted: start with row column scan coupled with aggressive breakthroughs by advanced Sudoku techniques. The updated list of Solutions to level 3, level 4 and NYTimes Sudoku hard puzzle games: How to solve Sudoku hard puzzle games full list (includes very hard Sudoku). This Sudoku hard is an especially challenging puzzle rich with Sudoku digit patterns. It is in three zones or areas - row R2, column C5 and 9 cell top-middle major square. Never lose an opportunity for a valid cell hit by row column scan. It can also be helpful to mark the columns and rows with pencil marks to work through elimination methods. Abdlomax 3 yr. ago Alternately, if R4C3 6, digut [1,7] will appear in eithe of the cells R5C3, R6C3. If you just want today's word, you can jump straight to the end of this article for November 3's Wordle solution, for . That means, these two digits light up or affect the intersecting cell R6C1 and reduce its possible digit subset to single digit 3. The . Identify a second Single digit lock on 5 in R9C5, R9C6 by scan for 5 in R7, C4 -- R9C1 3 by possible digit DS elimination of 5 (because of single digit lock on 5 in R9) from possible digit subset [3,5] in R9C1 (because of [1,4] in C1). Let's see the effect of this Cycle (1,8). Elimination of four cells of column C6 for digit 1 by parallel scan is shown by blue arrows in Stage 2 solution figure below. R4C1 8 by reduction of 3 from DS [3,8] in C1 -- R5C1 3 by exception in C1 -- R5C7 8 by exception in R5. Specifically important is the disallowing of digit 5 in the empty cells of C3. These puzzles are Before going through the solution solve the puzzle first. It a Sudoku hard rich with learning potential. In the new paper, Dr. Getzin and his colleagues noted that termites were conspicuously missing from their study sites, and that they found no signs of root damage in grass that died after rainfall .

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how to solve new york times sudoku

how to solve new york times sudoku