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element. The last file is the PHP file where you have to add your PHP script to process your form data on submission. /* other junk here from above, cut out to save space */, //obviously change the #data to your form's id, //after ajax returned successful, submit form id "data2", then "data3", //no error, call function to load uploaded image, //use ajax to query the new image's link and return it, 'INSERT INTO image (name,image) VALUES (:name,:image)', Simple PHP Class used for uploading files and images, Sending extra input field data not located on the form, Inserting an Image into a Database Table BLOB field, how could i display in console.log the contents of formData. You can also toggle between hiding and showing an element by using toggle () method. Read. Using the following method, you can submit multiple files and are not just limited to one. So let's checkout all steps one by one with easy way. YourFormBean class : @lombok.Getter @lombok.Setter @lombok.NoArgsConstructor public class YourFormBean { private String param1; private String param2; private boolean param3; } Controller code : @RequestMapping (value = "/actions/postForm", method = RequestMethod.POST) public String saveForm (Model model, @RequestParam ("additionalParam . Let's submit a form using click event and without using click event. How do refresh the image content when succesfully uploaded without page reload? the page not communicate with php page !!!!! You can use submit() in two ways either as a method or an event. Along with specifying the source you may send data along with it. Now, of course, I have to add a WYSIWYG editor to the mix and need to figure out how to get the html content to submit properly. Step 3 Handling Form Submit Logic in JavaScript and jQuery To submit a form via AJAX, your script will need to handle four tasks: Capture the form submit button so that the default action does not take place. The post method is used to load data by using the HTTP request. when a submit event occurs. Retrieve form elements from all pages using $() jQuery DataTables API method; Encode a set of form elements as an array of names and values using serializeArray() jQuery method; For each element in the . the
jquery submit form data